Solve {l}{-3/7{(2x+4)}-4=-1}{y={(-3*1)}+5}{text{Solvefor}ztext{where}}{z=y}

$$\left. \begin{array} { l } { -\frac{3}{7} {(2 x + 4)} - 4 = -1 }\\ { y = {(-3 \cdot 1)} + 5 }\\ { \text{Solve for } z \text{ where} } \\ { z = y } \end{array} \right.$$

Solve for x, y, z

$$z=2$$

Solution Steps

Consider the first equation. Use the distributive property to multiply -\frac{3}{7} by 2x+4.

$$-\frac{6}{7}x-\frac{12}{7}-4=-1$$

Subtract 4 from -\frac{12}{7} to get -\frac{40}{7}.

$$-\frac{6}{7}x-\frac{40}{7}=-1$$

Add \frac{40}{7} to both sides.

$$-\frac{6}{7}x=-1+\frac{40}{7}$$

Add -1 and \frac{40}{7} to get \frac{33}{7}.

$$-\frac{6}{7}x=\frac{33}{7}$$

Multiply both sides by -\frac{7}{6}, the reciprocal of -\frac{6}{7}.

$$x=\frac{33}{7}\left(-\frac{7}{6}\right)$$

Multiply \frac{33}{7} and -\frac{7}{6} to get -\frac{11}{2}.

$$x=-\frac{11}{2}$$

Consider the second equation. Multiply -3 and 1 to get -3.

$$y=-3+5$$

Add -3 and 5 to get 2.

$$y=2$$

Consider the third equation. Insert the known values of variables into the equation.

$$z=2$$

The system is now solved.

$$x=-\frac{11}{2} y=2 z=2$$