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Solve for y, z, a
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-\frac{1}{2}\times \frac{8}{3}=y
Consider the first equation. Multiply both sides by \frac{8}{3}, the reciprocal of \frac{3}{8}.
-\frac{4}{3}=y
Multiply -\frac{1}{2} and \frac{8}{3} to get -\frac{4}{3}.
y=-\frac{4}{3}
Swap sides so that all variable terms are on the left hand side.
z=-\frac{4}{3}
Consider the second equation. Insert the known values of variables into the equation.
a=-\frac{4}{3}
Consider the third equation. Insert the known values of variables into the equation.
y=-\frac{4}{3} z=-\frac{4}{3} a=-\frac{4}{3}
The system is now solved.