Solve {l}{{(x-3)}=24000}{y=x{(x-1)}{(x-2)}}{text{Solvefor}ztext{where}}{z=y}

$$\left. \begin{array} { l } { {(x - 3)} = 24000 }\\ { y = x {(x - 1)} {(x - 2)} }\\ { \text{Solve for } z \text{ where} } \\ { z = y } \end{array} \right.$$

Solve for x, y, z

$$z=13827456264006$$

Solution Steps

Consider the first equation. Add 3 to both sides.

$$x=24000+3$$

Add 24000 and 3 to get 24003.

$$x=24003$$

Consider the second equation. Insert the known values of variables into the equation.

$$y=24003\left(24003-1\right)\left(24003-2\right)$$

Subtract 1 from 24003 to get 24002.

$$y=24003\times 24002\left(24003-2\right)$$

Multiply 24003 and 24002 to get 576120006.

$$y=576120006\left(24003-2\right)$$

Subtract 2 from 24003 to get 24001.

$$y=576120006\times 24001$$

Multiply 576120006 and 24001 to get 13827456264006.

$$y=13827456264006$$

Consider the third equation. Insert the known values of variables into the equation.

$$z=13827456264006$$

The system is now solved.

$$x=24003 y=13827456264006 z=13827456264006$$