Solve for y, j, k
k=5.4
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5iy=3
Consider the first equation. Add 3 to both sides. Anything plus zero gives itself.
y=\frac{3}{5i}
Divide both sides by 5i.
y=\frac{3i}{-5}
Multiply both numerator and denominator of \frac{3}{5i} by imaginary unit i.
y=-\frac{3}{5}i
Divide 3i by -5 to get -\frac{3}{5}i.
y=-\frac{3}{5}i j=5.4 k=5.4
The system is now solved.
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