Solve {l}{{(6)}3/4x+3/8x=1}{y=75}{text{Solvefor}ztext{where}}{z=y}

$$\left. \begin{array} { l } { {(6)} \frac{3}{4} x + \frac{3}{8} x = 1 }\\ { y = 75 }\\ { \text{Solve for } z \text{ where} } \\ { z = y } \end{array} \right.$$

Solve for x, y, z

$$z=75$$

Solution Steps

Consider the first equation. Multiply 6 and \frac{3}{4} to get \frac{9}{2}.

$$\frac{9}{2}x+\frac{3}{8}x=1$$

Combine \frac{9}{2}x and \frac{3}{8}x to get \frac{39}{8}x.

$$\frac{39}{8}x=1$$

Multiply both sides by \frac{8}{39}, the reciprocal of \frac{39}{8}.

$$x=1\times \frac{8}{39}$$

Multiply 1 and \frac{8}{39} to get \frac{8}{39}.

$$x=\frac{8}{39}$$

The system is now solved.

$$x=\frac{8}{39} y=75 z=75$$