Solve {l}{{(4)}=3z+4/5}{a={(-2.3-4)}}{text{Solvefor}btext{where}}{b=a}

$$\left. \begin{array} { l } { {(4)} = \frac{3 z + 4}{5} }\\ { a = {(-2.3 - 4)} }\\ { \text{Solve for } b \text{ where} } \\ { b = a } \end{array} \right.$$

Solve for z, a, b

$$b=-6.3$$

Solution Steps

Consider the first equation. Multiply both sides by 5.

$$4\times 5=3z+4$$

Multiply 4 and 5 to get 20.

$$20=3z+4$$

Swap sides so that all variable terms are on the left hand side.

$$3z+4=20$$

Subtract 4 from both sides.

$$3z=20-4$$

Subtract 4 from 20 to get 16.

$$3z=16$$

Divide both sides by 3.

$$z=\frac{16}{3}$$

Consider the second equation. Subtract 4 from -2.3 to get -6.3.

$$a=-6.3$$

Consider the third equation. Insert the known values of variables into the equation.

$$b=-6.3$$

The system is now solved.

$$z=\frac{16}{3} a=-6.3 b=-6.3$$