Solve {l}{{(4x-3)}*0.25=1/4}{y=x}{z=y}{text{Solvefor}atext{where}}{a=z}

$$\left. \begin{array} { l } { {(4 x - 3)} \cdot 0.25 = \frac{1}{4} }\\ { y = x }\\ { z = y }\\ { \text{Solve for } a \text{ where} } \\ { a = z } \end{array} \right.$$

Solve for x, y, z, a

$$a=1$$

Solution Steps

Consider the first equation. Divide both sides by 0.25.

$$4x-3=\frac{\frac{1}{4}}{0.25}$$

Divide \frac{1}{4} by 0.25 to get 1.

$$4x-3=1$$

Add 3 to both sides.

$$4x=1+3$$

Add 1 and 3 to get 4.

$$4x=4$$

Divide both sides by 4.

$$x=\frac{4}{4}$$

Divide 4 by 4 to get 1.

$$x=1$$

Consider the second equation. Insert the known values of variables into the equation.

$$y=1$$

Consider the third equation. Insert the known values of variables into the equation.

$$z=1$$

Consider the fourth equation. Insert the known values of variables into the equation.

$$a=1$$

The system is now solved.

$$x=1 y=1 z=1 a=1$$