Solve {l}{{(4*5-x)}*3-1*6=0}{y=2}{text{Solvefor}ztext{where}}{z=y}

$$\left. \begin{array} { l } { {(4 \cdot 5 - x)} \cdot 3 - 1 \cdot 6 = 0 }\\ { y = 2 }\\ { \text{Solve for } z \text{ where} } \\ { z = y } \end{array} \right.$$

Solve for x, y, z

$$z=2$$

Solution Steps

Consider the first equation. Multiply 4 and 5 to get 20.

$$\left(20-x\right)\times 3-1\times 6=0$$

Use the distributive property to multiply 20-x by 3.

$$60-3x-1\times 6=0$$

Multiply 1 and 6 to get 6.

$$60-3x-6=0$$

Subtract 6 from 60 to get 54.

$$54-3x=0$$

Subtract 54 from both sides. Anything subtracted from zero gives its negation.

$$-3x=-54$$

Divide both sides by -3.

$$x=\frac{-54}{-3}$$

Divide -54 by -3 to get 18.

$$x=18$$

The system is now solved.

$$x=18 y=2 z=2$$