Solve {l}{{(3m-7)}*0*6-0*8{(4m-5)}-{(-1*7-1*4m)}=1}{n=5}{text{Solvefor}otext{where}}{o=n}

$$\left. \begin{array} { l } { {(3 m - 7)} \cdot 0 \cdot 6 - 0 \cdot 8 {(4 m - 5)} - {(-1 \cdot 7 - 1 \cdot 4 m)} = 1 }\\ { n = 5 }\\ { \text{Solve for } o \text{ where} } \\ { o = n } \end{array} \right.$$

Solve for m, n, o

$$o=5$$

Solution Steps

Consider the first equation. Multiply 0 and 6 to get 0.

$$\left(3m-7\right)\times 0-0\times 8\left(4m-5\right)-\left(-7-1\times 4m\right)=1$$

Anything times zero gives zero.

$$0-0\times 8\left(4m-5\right)-\left(-7-1\times 4m\right)=1$$

Multiply 0 and 8 to get 0.

$$0-0\left(4m-5\right)-\left(-7-1\times 4m\right)=1$$

Anything times zero gives zero.

$$0-0-\left(-7-1\times 4m\right)=1$$

Subtracting 0 from itself leaves 0.

$$0-\left(-7-1\times 4m\right)=1$$

Multiply 1 and 4 to get 4.

$$0-\left(-7-4m\right)=1$$

To find the opposite of -7-4m, find the opposite of each term.

$$0+7+4m=1$$

Add 0 and 7 to get 7.

$$7+4m=1$$

Subtract 7 from both sides.

$$4m=1-7$$

Subtract 7 from 1 to get -6.

$$4m=-6$$

Divide both sides by 4.

$$m=\frac{-6}{4}$$

Reduce the fraction \frac{-6}{4} to lowest terms by extracting and canceling out 2.

$$m=-\frac{3}{2}$$

The system is now solved.

$$m=-\frac{3}{2} n=5 o=5$$