Solve for x, y, z
z=1
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28+198x=-x
Consider the first equation. Multiply 3 and 66 to get 198.
28+198x+x=0
Add x to both sides.
28+199x=0
Combine 198x and x to get 199x.
199x=-28
Subtract 28 from both sides. Anything subtracted from zero gives its negation.
x=-\frac{28}{199}
Divide both sides by 199.
x=-\frac{28}{199} y=1 z=1
The system is now solved.
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