Solve {l}{{(2000-x)}=96}{y=.03x+.06}{text{Solvefor}ztext{where}}{z=y}

$$\left. \begin{array} { l } { {(2000 - x)} = 96 }\\ { y = .03 x + .06 }\\ { \text{Solve for } z \text{ where} } \\ { z = y } \end{array} \right.$$

Solve for x, y, z

$$z=57.18$$

Solution Steps

Consider the first equation. Subtract 2000 from both sides.

$$-x=96-2000$$

Subtract 2000 from 96 to get -1904.

$$-x=-1904$$

Divide both sides by -1.

$$x=\frac{-1904}{-1}$$

Fraction \frac{-1904}{-1} can be simplified to 1904 by removing the negative sign from both the numerator and the denominator.

$$x=1904$$

Consider the second equation. Insert the known values of variables into the equation.

$$y=0.03\times 1904+0.06$$

Multiply 0.03 and 1904 to get 57.12.

$$y=57.12+0.06$$

Add 57.12 and 0.06 to get 57.18.

$$y=57.18$$

Consider the third equation. Insert the known values of variables into the equation.

$$z=57.18$$

The system is now solved.

$$x=1904 y=57.18 z=57.18$$