Solve {l}{{(2*37+x)}-7*3=2}{y=77}{z=y}{a=z}{b=a}{c=b}{text{Solvefor}dtext{where}}{d=c}

$$\left. \begin{array} { l } { {(2 \cdot 37 + x)} - 7 \cdot 3 = 2 }\\ { y = 77 }\\ { z = y }\\ { a = z }\\ { b = a }\\ { c = b }\\ { \text{Solve for } d \text{ where} } \\ { d = c } \end{array} \right.$$

Solve for x, y, z, a, b, c, d

$$d=77$$

Solution Steps

Consider the first equation. Multiply 2 and 37 to get 74.

$$74+x-7\times 3=2$$

Multiply 7 and 3 to get 21.

$$74+x-21=2$$

Subtract 21 from 74 to get 53.

$$53+x=2$$

Subtract 53 from both sides.

$$x=2-53$$

Subtract 53 from 2 to get -51.

$$x=-51$$

The system is now solved.

$$x=-51 y=77 z=77 a=77 b=77 c=77 d=77$$