Solve {l}{{(frac{2*{(3)}+2}{3})}x-5*1=3}{y=7}{text{Solvefor}ztext{where}}{z=y}

$$\left. \begin{array} { l } { {(\frac{2 \cdot {(3)} + 2}{3})} x - 5 \cdot 1 = 3 }\\ { y = 7 }\\ { \text{Solve for } z \text{ where} } \\ { z = y } \end{array} \right.$$

Solve for x, y, z

$$z=7$$

Solution Steps

Consider the first equation. Multiply both sides of the equation by 3.

$$\left(2\times 3+2\right)x-15\times 1=9$$

Multiply 2 and 3 to get 6.

$$\left(6+2\right)x-15\times 1=9$$

Add 6 and 2 to get 8.

$$8x-15\times 1=9$$

Multiply 15 and 1 to get 15.

$$8x-15=9$$

Add 15 to both sides.

$$8x=9+15$$

Add 9 and 15 to get 24.

$$8x=24$$

Divide both sides by 8.

$$x=\frac{24}{8}$$

Divide 24 by 8 to get 3.

$$x=3$$

The system is now solved.

$$x=3 y=7 z=7$$