Solve {l}{sqrt{9}+B=23}{sqrt{4}+A=1^2}{a=A+B}{text{Solvefor}btext{where}}{b=a}

$$\left. \begin{array} { l } { \sqrt{9} + B = 23 }\\ { \sqrt{4} + A = 1 ^ {2} }\\ { a = A + B }\\ { \text{Solve for } b \text{ where} } \\ { b = a } \end{array} \right.$$

Solve for B, A, a, b

$$b=19$$

Solution Steps

Consider the first equation. Calculate the square root of 9 and get 3.

$$3+B=23$$

Subtract 3 from both sides.

$$B=23-3$$

Subtract 3 from 23 to get 20.

$$B=20$$

Consider the second equation. Calculate the square root of 4 and get 2.

$$2+A=1^{2}$$

Calculate 1 to the power of 2 and get 1.

$$2+A=1$$

Subtract 2 from both sides.

$$A=1-2$$

Subtract 2 from 1 to get -1.

$$A=-1$$

Consider the third equation. Insert the known values of variables into the equation.

$$a=-1+20$$

Add -1 and 20 to get 19.

$$a=19$$

Consider the fourth equation. Insert the known values of variables into the equation.

$$b=19$$

The system is now solved.

$$B=20 A=-1 a=19 b=19$$