Solve {l}{y+3/2-{(1-y)}=3}{z=5}{text{Solvefor}atext{where}}{a=z}

$$\left. \begin{array} { l } { \frac{y + 3}{2} - {(1 - y)} = 3 }\\ { z = 5 }\\ { \text{Solve for } a \text{ where} } \\ { a = z } \end{array} \right.$$

Solve for y, z, a

$$a=5$$

Solution Steps

Consider the first equation. Multiply both sides of the equation by 2.

$$y+3-2\left(1-y\right)=6$$

Use the distributive property to multiply -2 by 1-y.

$$y+3-2+2y=6$$

Subtract 2 from 3 to get 1.

$$y+1+2y=6$$

Combine y and 2y to get 3y.

$$3y+1=6$$

Subtract 1 from both sides.

$$3y=6-1$$

Subtract 1 from 6 to get 5.

$$3y=5$$

Divide both sides by 3.

$$y=\frac{5}{3}$$

The system is now solved.

$$y=\frac{5}{3} z=5 a=5$$