Solve {l}{x/3+x*5*47=2}{y=70}{text{Solvefor}ztext{where}}{z=y}

$$\left. \begin{array} { l } { \frac{x}{3 + x} \cdot 5 \cdot 47 = 2 }\\ { y = 70 }\\ { \text{Solve for } z \text{ where} } \\ { z = y } \end{array} \right.$$

Solve for x, y, z

$$z=70$$

Solution Steps

Consider the first equation. Variable x cannot be equal to -3 since division by zero is not defined. Multiply both sides of the equation by x+3.

$$x\times 5\times 47=2\left(x+3\right)$$

Multiply 5 and 47 to get 235.

$$x\times 235=2\left(x+3\right)$$

Use the distributive property to multiply 2 by x+3.

$$x\times 235=2x+6$$

Subtract 2x from both sides.

$$x\times 235-2x=6$$

Combine x\times 235 and -2x to get 233x.

$$233x=6$$

Divide both sides by 233.

$$x=\frac{6}{233}$$

The system is now solved.

$$x=\frac{6}{233} y=70 z=70$$