Solve for x, y, z, a, b
b=0
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x+96=12\left(x+2\right)\times 4
Consider the first equation. Multiply both sides of the equation by 12.
x+96=48\left(x+2\right)
Multiply 12 and 4 to get 48.
x+96=48x+96
Use the distributive property to multiply 48 by x+2.
x+96-48x=96
Subtract 48x from both sides.
-47x+96=96
Combine x and -48x to get -47x.
-47x=96-96
Subtract 96 from both sides.
-47x=0
Subtract 96 from 96 to get 0.
x=0
Divide both sides by -47. Zero divided by any non-zero number gives zero.
x=0 y=0 z=0 a=0 b=0
The system is now solved.
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