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Solve for x, y, z
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3\left(x+3\right)+12x\left(-\frac{1}{2}\right)=x-1+12x\times \frac{1}{12}
Consider the first equation. Variable x cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by 12x, the least common multiple of 4x,2,12x,12.
3x+9+12x\left(-\frac{1}{2}\right)=x-1+12x\times \frac{1}{12}
Use the distributive property to multiply 3 by x+3.
3x+9-6x=x-1+12x\times \frac{1}{12}
Multiply 12 and -\frac{1}{2} to get -6.
-3x+9=x-1+12x\times \frac{1}{12}
Combine 3x and -6x to get -3x.
-3x+9=x-1+x
Multiply 12 and \frac{1}{12} to get 1.
-3x+9=2x-1
Combine x and x to get 2x.
-3x+9-2x=-1
Subtract 2x from both sides.
-5x+9=-1
Combine -3x and -2x to get -5x.
-5x=-1-9
Subtract 9 from both sides.
-5x=-10
Subtract 9 from -1 to get -10.
x=\frac{-10}{-5}
Divide both sides by -5.
x=2
Divide -10 by -5 to get 2.
y=12\times 2-9\times 4\times 2-5
Consider the second equation. Insert the known values of variables into the equation.
y=24-9\times 4\times 2-5
Multiply 12 and 2 to get 24.
y=24-36\times 2-5
Multiply 9 and 4 to get 36.
y=24-72-5
Multiply 36 and 2 to get 72.
y=-48-5
Subtract 72 from 24 to get -48.
y=-53
Subtract 5 from -48 to get -53.
z=-53
Consider the third equation. Insert the known values of variables into the equation.
x=2 y=-53 z=-53
The system is now solved.