Solve for x, y, z
z=3
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x=\frac{2}{3}\times \frac{3}{7}
Consider the first equation. Multiply both sides by \frac{3}{7}, the reciprocal of \frac{7}{3}.
x=\frac{2}{7}
Multiply \frac{2}{3} and \frac{3}{7} to get \frac{2}{7}.
x=\frac{2}{7} y=3 z=3
The system is now solved.
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