Solve for x, y, z
z=-3
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x\times 5=\left(x-2\right)\times 3
Consider the first equation. Variable x cannot be equal to any of the values 0,2 since division by zero is not defined. Multiply both sides of the equation by x\left(x-2\right), the least common multiple of x-2,x.
x\times 5=3x-6
Use the distributive property to multiply x-2 by 3.
x\times 5-3x=-6
Subtract 3x from both sides.
2x=-6
Combine x\times 5 and -3x to get 2x.
x=\frac{-6}{2}
Divide both sides by 2.
x=-3
Divide -6 by 2 to get -3.
x=-3 y=-3 z=-3
The system is now solved.
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