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Solve for x, y, z
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2\times 4\left(x-1\right)-3\left(2x-3\right)=0
Consider the first equation. Multiply both sides of the equation by 6, the least common multiple of 3,2.
8\left(x-1\right)-3\left(2x-3\right)=0
Multiply 2 and 4 to get 8.
8x-8-3\left(2x-3\right)=0
Use the distributive property to multiply 8 by x-1.
8x-8-6x+9=0
Use the distributive property to multiply -3 by 2x-3.
2x-8+9=0
Combine 8x and -6x to get 2x.
2x+1=0
Add -8 and 9 to get 1.
2x=-1
Subtract 1 from both sides. Anything subtracted from zero gives its negation.
x=-\frac{1}{2}
Divide both sides by 2.
x=-\frac{1}{2} y=5 z=5
The system is now solved.