Solve for x, y, z
z=-12
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\frac{3}{4}x=-8-1
Consider the first equation. Subtract 1 from both sides.
\frac{3}{4}x=-9
Subtract 1 from -8 to get -9.
x=-9\times \frac{4}{3}
Multiply both sides by \frac{4}{3}, the reciprocal of \frac{3}{4}.
x=-12
Multiply -9 and \frac{4}{3} to get -12.
x=-12 y=-12 z=-12
The system is now solved.
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