Solve for x, y, z
x=\frac{9a}{8}+3
y=a
z=a
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z=y \frac{2}{3}x-\frac{3}{4}y=2 a=z
Reorder the equations.
a=y
Substitute y for z in the equation a=z.
x=\frac{9}{8}y+3 y=a
Solve the second equation for x and the third equation for y.
x=\frac{9}{8}a+3
Substitute a for y in the equation x=\frac{9}{8}y+3.
z=a
Substitute a for y in the equation z=y.
x=\frac{9}{8}a+3 y=a z=a
The system is now solved.
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