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Solve for x, y, z, a, b, c, d
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\frac{2}{3}x+\frac{1}{5}=\frac{1}{5}
Consider the first equation. Reduce the fraction \frac{2}{10} to lowest terms by extracting and canceling out 2.
\frac{2}{3}x=\frac{1}{5}-\frac{1}{5}
Subtract \frac{1}{5} from both sides.
\frac{2}{3}x=0
Subtract \frac{1}{5} from \frac{1}{5} to get 0.
x=0
Multiply both sides by \frac{3}{2}, the reciprocal of \frac{2}{3}. Anything times zero gives zero.
y=0+8
Consider the second equation. The opposite of -8 is 8.
y=8
Add 0 and 8 to get 8.
z=8
Consider the third equation. Insert the known values of variables into the equation.
a=8
Consider the fourth equation. Insert the known values of variables into the equation.
b=8
Consider the fifth equation. Insert the known values of variables into the equation.
c=8
Consider the equation (6). Insert the known values of variables into the equation.
d=8
Consider the equation (7). Insert the known values of variables into the equation.
x=0 y=8 z=8 a=8 b=8 c=8 d=8
The system is now solved.