Solve {l}{2/3n+4=-26}{o=2+7}{text{Solvefor}ptext{where}}{p=o}

$$\left. \begin{array} { l } { \frac{2}{3} n + 4 = -26 }\\ { o = 2 + 7 }\\ { \text{Solve for } p \text{ where} } \\ { p = o } \end{array} \right.$$

Solve for n, o, p

$$p=9$$

Solution Steps

Consider the first equation. Subtract 4 from both sides.

$$\frac{2}{3}n=-26-4$$

Subtract 4 from -26 to get -30.

$$\frac{2}{3}n=-30$$

Multiply both sides by \frac{3}{2}, the reciprocal of \frac{2}{3}.

$$n=-30\times \frac{3}{2}$$

Multiply -30 and \frac{3}{2} to get -45.

$$n=-45$$

Consider the second equation. Add 2 and 7 to get 9.

$$o=9$$

Consider the third equation. Insert the known values of variables into the equation.

$$p=9$$

The system is now solved.

$$n=-45 o=9 p=9$$