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Solve for x, y, z
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\left(x+500\right)\times 150=1000x
Consider the first equation. Variable x cannot be equal to -500 since division by zero is not defined. Multiply both sides of the equation by 1000\left(x+500\right), the least common multiple of 1000,x+500.
150x+75000=1000x
Use the distributive property to multiply x+500 by 150.
150x+75000-1000x=0
Subtract 1000x from both sides.
-850x+75000=0
Combine 150x and -1000x to get -850x.
-850x=-75000
Subtract 75000 from both sides. Anything subtracted from zero gives its negation.
x=\frac{-75000}{-850}
Divide both sides by -850.
x=\frac{1500}{17}
Reduce the fraction \frac{-75000}{-850} to lowest terms by extracting and canceling out -50.
y=\frac{1500}{17}
Consider the second equation. Insert the known values of variables into the equation.
z=\frac{1500}{17}
Consider the third equation. Insert the known values of variables into the equation.
x=\frac{1500}{17} y=\frac{1500}{17} z=\frac{1500}{17}
The system is now solved.