Solve {l}{12/104=3600*8/x}{y=x}{text{Solvefor}ztext{where}}{z=y}

$$\left. \begin{array} { l } { \frac{12}{104} = \frac{3600 \cdot 8}{x} }\\ { y = x }\\ { \text{Solve for } z \text{ where} } \\ { z = y } \end{array} \right.$$

Solve for x, y, z

$$z=249600$$

Solution Steps

Consider the first equation. Variable x cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by 104x, the least common multiple of 104,x.

$$x\times 12=104\times 3600\times 8$$

Multiply 104 and 3600 to get 374400.

$$x\times 12=374400\times 8$$

Multiply 374400 and 8 to get 2995200.

$$x\times 12=2995200$$

Divide both sides by 12.

$$x=\frac{2995200}{12}$$

Divide 2995200 by 12 to get 249600.

$$x=249600$$

Consider the second equation. Insert the known values of variables into the equation.

$$y=249600$$

Consider the third equation. Insert the known values of variables into the equation.

$$z=249600$$

The system is now solved.

$$x=249600 y=249600 z=249600$$