Solve {l}{1/4*{(8+4x)}+3=2}{y=5x-4}{z=y}{a=z}{b=a}{c=b}{text{Solvefor}dtext{where}}{d=c}

$$\left. \begin{array} { l } { \frac{1}{4} \cdot {(8 + 4 x)} + 3 = 2 }\\ { y = 5 x - 4 }\\ { z = y }\\ { a = z }\\ { b = a }\\ { c = b }\\ { \text{Solve for } d \text{ where} } \\ { d = c } \end{array} \right.$$

Solve for x, y, z, a, b, c, d

$$d=-19$$

Solution Steps

Consider the first equation. Use the distributive property to multiply \frac{1}{4} by 8+4x.

$$2+x+3=2$$

Add 2 and 3 to get 5.

$$5+x=2$$

Subtract 5 from both sides.

$$x=2-5$$

Subtract 5 from 2 to get -3.

$$x=-3$$

Consider the second equation. Insert the known values of variables into the equation.

$$y=5\left(-3\right)-4$$

Multiply 5 and -3 to get -15.

$$y=-15-4$$

Subtract 4 from -15 to get -19.

$$y=-19$$

Consider the third equation. Insert the known values of variables into the equation.

$$z=-19$$

Consider the fourth equation. Insert the known values of variables into the equation.

$$a=-19$$

Consider the fifth equation. Insert the known values of variables into the equation.

$$b=-19$$

Consider the equation (6). Insert the known values of variables into the equation.

$$c=-19$$

Consider the equation (7). Insert the known values of variables into the equation.

$$d=-19$$

The system is now solved.

$$x=-3 y=-19 z=-19 a=-19 b=-19 c=-19 d=-19$$