Solve for x, y, z, a, b, c
c=2
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3\left(1\times 5x+1\right)+0\times 2x=6
Consider the first equation. Multiply both sides of the equation by 6, the least common multiple of 2,6.
3\left(5x+1\right)+0\times 2x=6
Multiply 1 and 5 to get 5.
15x+3+0\times 2x=6
Use the distributive property to multiply 3 by 5x+1.
15x+3+0x=6
Multiply 0 and 2 to get 0.
15x+3+0=6
Anything times zero gives zero.
15x+3=6
Add 3 and 0 to get 3.
15x=6-3
Subtract 3 from both sides.
15x=3
Subtract 3 from 6 to get 3.
x=\frac{3}{15}
Divide both sides by 15.
x=\frac{1}{5}
Reduce the fraction \frac{3}{15} to lowest terms by extracting and canceling out 3.
x=\frac{1}{5} y=2 z=2 a=2 b=2 c=2
The system is now solved.
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