Solve {l|l}hline0.21&{0.2}hline0.08&{0.1}

$$\left. \begin{array} { l | l } \hline 0.21 & { 0.2 } \\ \hline 0.08 & { 0.1 } \end{array} \right.$$

Calculate Determinant

$$0.005$$

Steps Using Diagonal Rule

Find the determinant of the matrix.

$$det(\left(\begin{matrix}0.21&0.2\\0.08&0.1\end{matrix}\right))$$

For the 2\times 2 matrix \left(\begin{matrix}a&b\\c&d\end{matrix}\right), the determinant is ad-bc.

$$0.21\times 0.1-0.2\times 0.08$$

Multiply 0.21 times 0.1 by multiplying numerator times numerator and denominator times denominator. Then reduce the fraction to lowest terms if possible.

$$0.021-0.2\times 0.08$$

Multiply 0.2 times 0.08 by multiplying numerator times numerator and denominator times denominator. Then reduce the fraction to lowest terms if possible.

$$0.021-0.016$$

Subtract 0.016 from 0.021 by finding a common denominator and subtracting the numerators. Then reduce the fraction to lowest terms if possible.

$$0.005$$

Evaluate

$$\left(\begin{matrix}0.21&0.2\\0.08&0.1\end{matrix}\right)$$