Skip to main content
Calculate Determinant
Tick mark Image
Evaluate
Tick mark Image

Share

det(\left(\begin{matrix}9&4&6\\5&7&7\\b&8&6\end{matrix}\right))
Find the determinant of the matrix using the method of diagonals.
\left(\begin{matrix}9&4&6&9&4\\5&7&7&5&7\\b&8&6&b&8\end{matrix}\right)
Extend the original matrix by repeating the first two columns as the fourth and fifth columns.
9\times 7\times 6+4\times 7b+6\times 5\times 8=28b+618
Starting at the upper left entry, multiply down along the diagonals, and add the resulting products.
b\times 7\times 6+8\times 7\times 9+6\times 5\times 4=42b+624
Starting at the lower left entry, multiply up along the diagonals, and add the resulting products.
28b+618-\left(42b+624\right)
Subtract the sum of the upward diagonal products from the sum of the downward diagonal products.
-14b-6
Subtract 42b+624 from 618+28b.
det(\left(\begin{matrix}9&4&6\\5&7&7\\b&8&6\end{matrix}\right))
Find the determinant of the matrix using the method of expansion by minors (also known as expansion by cofactors).
9det(\left(\begin{matrix}7&7\\8&6\end{matrix}\right))-4det(\left(\begin{matrix}5&7\\b&6\end{matrix}\right))+6det(\left(\begin{matrix}5&7\\b&8\end{matrix}\right))
To expand by minors, multiply each element of the first row by its minor, which is the determinant of the 2\times 2 matrix created by deleting the row and column containing that element, then multiply by the element's position sign.
9\left(7\times 6-8\times 7\right)-4\left(5\times 6-b\times 7\right)+6\left(5\times 8-b\times 7\right)
For the 2\times 2 matrix \left(\begin{matrix}a&b\\c&d\end{matrix}\right), the determinant is ad-bc.
9\left(-14\right)-4\left(30-7b\right)+6\left(40-7b\right)
Simplify.
-14b-6
Add the terms to obtain the final result.