Solve {c}{y=x^2+300x+19561}{x=-191}

$$\left. \begin{array} { c } { y = x ^ { 2 } + 300 x + 19561 } \\ { x = - 191 } \end{array} \right.$$

Solve for y, x

$$x=-191$$

$$y=-1258$$

Solution Steps

Consider the first equation. Insert the known values of variables into the equation.

$$y=\left(-191\right)^{2}+300\left(-191\right)+19561$$

Calculate -191 to the power of 2 and get 36481.

$$y=36481+300\left(-191\right)+19561$$

Multiply 300 and -191 to get -57300.

$$y=36481-57300+19561$$

Subtract 57300 from 36481 to get -20819.

$$y=-20819+19561$$

Add -20819 and 19561 to get -1258.

$$y=-1258$$

The system is now solved.

$$y=-1258 x=-191$$