Solve {c}{y=x^2+300x+19561}{x=-161}

$$\left. \begin{array} { c } { y = x ^ { 2 } + 300 x + 19561 } \\ { x = - 161 } \end{array} \right.$$

Solve for y, x

$$x=-161$$

$$y=-2818$$

Solution Steps

Consider the first equation. Insert the known values of variables into the equation.

$$y=\left(-161\right)^{2}+300\left(-161\right)+19561$$

Calculate -161 to the power of 2 and get 25921.

$$y=25921+300\left(-161\right)+19561$$

Multiply 300 and -161 to get -48300.

$$y=25921-48300+19561$$

Subtract 48300 from 25921 to get -22379.

$$y=-22379+19561$$

Add -22379 and 19561 to get -2818.

$$y=-2818$$

The system is now solved.

$$y=-2818 x=-161$$