Solve {c}{y=x^2+300x+19561}{x=-131}

$$\left. \begin{array} { c } { y = x ^ { 2 } + 300 x + 19561 } \\ { x = - 131 } \end{array} \right.$$

Solve for y, x

$$x=-131$$

$$y=-2578$$

Solution Steps

Consider the first equation. Insert the known values of variables into the equation.

$$y=\left(-131\right)^{2}+300\left(-131\right)+19561$$

Calculate -131 to the power of 2 and get 17161.

$$y=17161+300\left(-131\right)+19561$$

Multiply 300 and -131 to get -39300.

$$y=17161-39300+19561$$

Subtract 39300 from 17161 to get -22139.

$$y=-22139+19561$$

Add -22139 and 19561 to get -2578.

$$y=-2578$$

The system is now solved.

$$y=-2578 x=-131$$