Solve {c}{y=x^2+300x+19561}{x=-101}

$$\left. \begin{array} { c } { y = x ^ { 2 } + 300 x + 19561 } \\ { x = - 101 } \end{array} \right.$$

Solve for y, x

$$x=-101$$

$$y=-538$$

Solution Steps

Consider the first equation. Insert the known values of variables into the equation.

$$y=\left(-101\right)^{2}+300\left(-101\right)+19561$$

Calculate -101 to the power of 2 and get 10201.

$$y=10201+300\left(-101\right)+19561$$

Multiply 300 and -101 to get -30300.

$$y=10201-30300+19561$$

Subtract 30300 from 10201 to get -20099.

$$y=-20099+19561$$

Add -20099 and 19561 to get -538.

$$y=-538$$

The system is now solved.

$$y=-538 x=-101$$