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Solve for y, a
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3a-12=6a-4+5a
Consider the second equation. Combine 2a and a to get 3a.
3a-12=11a-4
Combine 6a and 5a to get 11a.
3a-12-11a=-4
Subtract 11a from both sides.
-8a-12=-4
Combine 3a and -11a to get -8a.
-8a=-4+12
Add 12 to both sides.
-8a=8
Add -4 and 12 to get 8.
a=\frac{8}{-8}
Divide both sides by -8.
a=-1
Divide 8 by -8 to get -1.
y=16 a=-1
The system is now solved.