Solve for y, x
x=3
y=16
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y=\left(3^{2}-7\right)^{4}
Consider the first equation. Insert the known values of variables into the equation.
y=\left(9-7\right)^{4}
Calculate 3 to the power of 2 and get 9.
y=2^{4}
Subtract 7 from 9 to get 2.
y=16
Calculate 2 to the power of 4 and get 16.
y=16 x=3
The system is now solved.
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