Solve {c}{x*(-x)^3+(-x)*x^3}{-x^4*4}

$$\left. \begin{array} { c } { x \cdot ( - x ) ^ { 3 } + ( - x ) \cdot x ^ { 3 } } \\ { - x ^ { 4 } \cdot 4 } \end{array} \right.$$

Evaluate

$$-6x^{4}$$

Solution Steps

Expand \left(-x\right)^{3}.

$$x\left(-1\right)^{3}x^{3}-xx^{3}-x^{4}\times 4$$

Calculate -1 to the power of 3 and get -1.

$$x\left(-1\right)x^{3}-xx^{3}-x^{4}\times 4$$

To multiply powers of the same base, add their exponents. Add 1 and 3 to get 4.

$$x^{4}\left(-1\right)-xx^{3}-x^{4}\times 4$$

To multiply powers of the same base, add their exponents. Add 1 and 3 to get 4.

$$x^{4}\left(-1\right)-x^{4}-x^{4}\times 4$$

Combine x^{4}\left(-1\right) and -x^{4} to get -2x^{4}.

$$-2x^{4}-x^{4}\times 4$$

Multiply -1 and 4 to get -4.

$$-2x^{4}-4x^{4}$$

Combine -2x^{4} and -4x^{4} to get -6x^{4}.

$$-6x^{4}$$

Expand

$$-6x^{4}$$

Solution Steps

Expand \left(-x\right)^{3}.

$$x\left(-1\right)^{3}x^{3}-xx^{3}-x^{4}\times 4$$

Calculate -1 to the power of 3 and get -1.

$$x\left(-1\right)x^{3}-xx^{3}-x^{4}\times 4$$

To multiply powers of the same base, add their exponents. Add 1 and 3 to get 4.

$$x^{4}\left(-1\right)-xx^{3}-x^{4}\times 4$$

To multiply powers of the same base, add their exponents. Add 1 and 3 to get 4.

$$x^{4}\left(-1\right)-x^{4}-x^{4}\times 4$$

Combine x^{4}\left(-1\right) and -x^{4} to get -2x^{4}.

$$-2x^{4}-x^{4}\times 4$$

Multiply -1 and 4 to get -4.

$$-2x^{4}-4x^{4}$$

Combine -2x^{4} and -4x^{4} to get -6x^{4}.

$$-6x^{4}$$