Solve {c}{x=2}{x-y+3=0}

$$\left. \begin{array} { c } { x = 2 } \\ { x - y + 3 = 0 } \end{array} \right.$$

Solve for x, y

$$x=2$$

$$y=5$$

Solution Steps

Consider the second equation. Insert the known values of variables into the equation.

$$2-y+3=0$$

Add 2 and 3 to get 5.

$$5-y=0$$

Subtract 5 from both sides. Anything subtracted from zero gives its negation.

$$-y=-5$$

Divide both sides by -1.

$$y=\frac{-5}{-1}$$

Fraction \frac{-5}{-1} can be simplified to 5 by removing the negative sign from both the numerator and the denominator.

$$y=5$$

The system is now solved.

$$x=2 y=5$$