Solve {c}{x=2}{f(x)=8x-2x^2}

$$\left. \begin{array} { c } { x = 2 } \\ { f ( x ) = 8 x - 2 x ^ { 2 } } \end{array} \right.$$

Solve for x, f

$$x=2$$

$$f=4$$

Solution Steps

Consider the second equation. Insert the known values of variables into the equation.

$$f\times 2=8\times 2-2\times 2^{2}$$

Multiply 8 and 2 to get 16.

$$f\times 2=16-2\times 2^{2}$$

Calculate 2 to the power of 2 and get 4.

$$f\times 2=16-2\times 4$$

Multiply -2 and 4 to get -8.

$$f\times 2=16-8$$

Subtract 8 from 16 to get 8.

$$f\times 2=8$$

Divide both sides by 2.

$$f=\frac{8}{2}$$

Divide 8 by 2 to get 4.

$$f=4$$

The system is now solved.

$$x=2 f=4$$