Solve {c}{x+y=3}{2y+5y=12}

$$\left. \begin{array} { c } { x + y = 3 } \\ { 2 y + 5 y = 12 } \end{array} \right.$$

Solve for x, y

$$x = \frac{9}{7} = 1\frac{2}{7} \approx 1.285714286$$

$$y = \frac{12}{7} = 1\frac{5}{7} \approx 1.714285714$$

Solution Steps

Consider the second equation. Combine 2y and 5y to get 7y.

$$7y=12$$

Divide both sides by 7.

$$y=\frac{12}{7}$$

Consider the first equation. Insert the known values of variables into the equation.

$$x+\frac{12}{7}=3$$

Subtract \frac{12}{7} from both sides.

$$x=3-\frac{12}{7}$$

Subtract \frac{12}{7} from 3 to get \frac{9}{7}.

$$x=\frac{9}{7}$$

The system is now solved.

$$x=\frac{9}{7} y=\frac{12}{7}$$