Solve {c}{x+4=12}{2x+4y=42}

$$\left. \begin{array} { c } { x + 4 = 12 } \\ { 2 x + 4 y = 42 } \end{array} \right.$$

Solve for x, y

$$x=8$$

$$y = \frac{13}{2} = 6\frac{1}{2} = 6.5$$

Solution Steps

Consider the first equation. Subtract 4 from both sides.

$$x=12-4$$

Subtract 4 from 12 to get 8.

$$x=8$$

Consider the second equation. Insert the known values of variables into the equation.

$$2\times 8+4y=42$$

Multiply 2 and 8 to get 16.

$$16+4y=42$$

Subtract 16 from both sides.

$$4y=42-16$$

Subtract 16 from 42 to get 26.

$$4y=26$$

Divide both sides by 4.

$$y=\frac{26}{4}$$

Reduce the fraction \frac{26}{4} to lowest terms by extracting and canceling out 2.

$$y=\frac{13}{2}$$

The system is now solved.

$$x=8 y=\frac{13}{2}$$