Solve {c}{x+3=43}{3x+4y=169}

$$\left. \begin{array} { c } { x + 3 = 43 } \\ { 3 x + 4 y = 169 } \end{array} \right.$$

Solve for x, y

$$x=40$$

$$y = \frac{49}{4} = 12\frac{1}{4} = 12.25$$

Solution Steps

Consider the first equation. Subtract 3 from both sides.

$$x=43-3$$

Subtract 3 from 43 to get 40.

$$x=40$$

Consider the second equation. Insert the known values of variables into the equation.

$$3\times 40+4y=169$$

Multiply 3 and 40 to get 120.

$$120+4y=169$$

Subtract 120 from both sides.

$$4y=169-120$$

Subtract 120 from 169 to get 49.

$$4y=49$$

Divide both sides by 4.

$$y=\frac{49}{4}$$

The system is now solved.

$$x=40 y=\frac{49}{4}$$