Solve {c}{m-25=3m-5}{B-m=-8}

$$\left. \begin{array} { c } { m - 25 = 3 m - 5 } \\ { B - m = - 8 } \end{array} \right.$$

Solve for m, B

$$m=-10$$

$$B=-18$$

Solution Steps

Consider the first equation. Subtract 3m from both sides.

$$m-25-3m=-5$$

Combine m and -3m to get -2m.

$$-2m-25=-5$$

Add 25 to both sides.

$$-2m=-5+25$$

Add -5 and 25 to get 20.

$$-2m=20$$

Divide both sides by -2.

$$m=\frac{20}{-2}$$

Divide 20 by -2 to get -10.

$$m=-10$$

Consider the second equation. Insert the known values of variables into the equation.

$$B-\left(-10\right)=-8$$

Multiply -1 and -10 to get 10.

$$B+10=-8$$

Subtract 10 from both sides.

$$B=-8-10$$

Subtract 10 from -8 to get -18.

$$B=-18$$

The system is now solved.

$$m=-10 B=-18$$