Solve for V, a
V=15
a = \frac{10}{3} = 3\frac{1}{3} \approx 3.333333333
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60=75-\frac{9}{2}a
Consider the second equation. Multiply 25 and 3 to get 75.
75-\frac{9}{2}a=60
Swap sides so that all variable terms are on the left hand side.
-\frac{9}{2}a=60-75
Subtract 75 from both sides.
-\frac{9}{2}a=-15
Subtract 75 from 60 to get -15.
a=-15\left(-\frac{2}{9}\right)
Multiply both sides by -\frac{2}{9}, the reciprocal of -\frac{9}{2}.
a=\frac{10}{3}
Multiply -15 and -\frac{2}{9} to get \frac{10}{3}.
V=25-3\times \frac{10}{3}
Consider the first equation. Insert the known values of variables into the equation.
V=25-10
Multiply -3 and \frac{10}{3} to get -10.
V=15
Subtract 10 from 25 to get 15.
V=15 a=\frac{10}{3}
The system is now solved.
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