Solve {c}{6x-8y+1=0}{x=5}

$$\left. \begin{array} { c } { 6 x - 8 y + 1 = 0 } \\ { x = 5 } \end{array} \right.$$

Solve for x, y

$$x=5$$

$$y = \frac{31}{8} = 3\frac{7}{8} = 3.875$$

Solution Steps

Consider the first equation. Insert the known values of variables into the equation.

$$6\times 5-8y+1=0$$

Multiply 6 and 5 to get 30.

$$30-8y+1=0$$

Add 30 and 1 to get 31.

$$31-8y=0$$

Subtract 31 from both sides. Anything subtracted from zero gives its negation.

$$-8y=-31$$

Divide both sides by -8.

$$y=\frac{-31}{-8}$$

Fraction \frac{-31}{-8} can be simplified to \frac{31}{8} by removing the negative sign from both the numerator and the denominator.

$$y=\frac{31}{8}$$

The system is now solved.

$$x=5 y=\frac{31}{8}$$