Solve {c}{34=6t+4}{14=6+z/-2}

$$\left. \begin{array} { c } { 34 = 6 t + 4 } \\ { 14 = \frac { 6 + z } { - 2 } } \end{array} \right.$$

Solve for t, z

$$z=-34$$

$$t=5$$

Solution Steps

Consider the first equation. Swap sides so that all variable terms are on the left hand side.

$$6t+4=34$$

Subtract 4 from both sides.

$$6t=34-4$$

Subtract 4 from 34 to get 30.

$$6t=30$$

Divide both sides by 6.

$$t=\frac{30}{6}$$

Divide 30 by 6 to get 5.

$$t=5$$

Consider the second equation. Multiply both sides by -2.

$$14\left(-2\right)=6+z$$

Multiply 14 and -2 to get -28.

$$-28=6+z$$

Swap sides so that all variable terms are on the left hand side.

$$6+z=-28$$

Subtract 6 from both sides.

$$z=-28-6$$

Subtract 6 from -28 to get -34.

$$z=-34$$

The system is now solved.

$$t=5 z=-34$$