Solve {c}{3x+y=1}{9-y=3}

$$\left. \begin{array} { c } { 3 x + y = 1 } \\ { 9 - y = 3 } \end{array} \right.$$

Solve for x, y

$$x = -\frac{5}{3} = -1\frac{2}{3} \approx -1.666666667$$

$$y=6$$

Solution Steps

Consider the second equation. Subtract 9 from both sides.

$$-y=3-9$$

Subtract 9 from 3 to get -6.

$$-y=-6$$

Divide both sides by -1.

$$y=\frac{-6}{-1}$$

Fraction \frac{-6}{-1} can be simplified to 6 by removing the negative sign from both the numerator and the denominator.

$$y=6$$

Consider the first equation. Insert the known values of variables into the equation.

$$3x+6=1$$

Subtract 6 from both sides.

$$3x=1-6$$

Subtract 6 from 1 to get -5.

$$3x=-5$$

Divide both sides by 3.

$$x=-\frac{5}{3}$$

The system is now solved.

$$x=-\frac{5}{3} y=6$$