Solve {c}{3x+4x=59}{y+x=18}

$$\left. \begin{array} { c } { 3 x + 4 x = 59 } \\ { y + x = 18 } \end{array} \right.$$

Solve for x, y

$$x = \frac{59}{7} = 8\frac{3}{7} \approx 8.428571429$$

$$y = \frac{67}{7} = 9\frac{4}{7} \approx 9.571428571$$

Solution Steps

Consider the first equation. Combine 3x and 4x to get 7x.

$$7x=59$$

Divide both sides by 7.

$$x=\frac{59}{7}$$

Consider the second equation. Insert the known values of variables into the equation.

$$y+\frac{59}{7}=18$$

Subtract \frac{59}{7} from both sides.

$$y=18-\frac{59}{7}$$

Subtract \frac{59}{7} from 18 to get \frac{67}{7}.

$$y=\frac{67}{7}$$

The system is now solved.

$$x=\frac{59}{7} y=\frac{67}{7}$$