Solve {c}{3x+2y=10}{x+2=20}

$$\left. \begin{array} { c } { 3 x + 2 y = 10 } \\ { x + 2 = 20 } \end{array} \right.$$

Solve for x, y

$$x=18$$

$$y=-22$$

Solution Steps

Consider the second equation. Subtract 2 from both sides.

$$x=20-2$$

Subtract 2 from 20 to get 18.

$$x=18$$

Consider the first equation. Insert the known values of variables into the equation.

$$3\times 18+2y=10$$

Multiply 3 and 18 to get 54.

$$54+2y=10$$

Subtract 54 from both sides.

$$2y=10-54$$

Subtract 54 from 10 to get -44.

$$2y=-44$$

Divide both sides by 2.

$$y=\frac{-44}{2}$$

Divide -44 by 2 to get -22.

$$y=-22$$

The system is now solved.

$$x=18 y=-22$$